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Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. When she began her study, the frog population was estimated at 1,200. Which function represents the frog population after x years?

User Tnilsson
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2 Answers

1 vote
Hello,


x_(0)=1200


x_(1)=(97)/(100)*1200


x_(2)=((97)/(100))^2*1200


x_(3)=((97)/(100))^3*1200
...

x_(n)=((97)/(100))^(n)*1200








User Sasha Fonseca
by
7.2k points
6 votes

Answer:


y = 1200(0.97)^x

Explanation:

Ginny determines that the population is decreasing at an average rate of 3% per year.

So, this is an exponential decay case

Formula :
y = a(1-r)^n

where a is the amount after n years

a is the initial amount

r is the rate of depreciate

n is the number of years

Now we are given that When she began her study, the frog population was estimated at 1,200.

So, a=1200

r = 3% = 0.03

n =x

Substitute the values in the formula:


y = 1200(1-0.03)^x


y = 1200(0.97)^x

Hence function represents the frog population after x years is
y = 1200(0.97)^x

User RononDex
by
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