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What is the equation of a line that is perpendicular to the line that goes through the points (0, -3) and (-3, 12)? y = 15x + 2 y = (-1/15x) - 8 y = -9x - 7 y = (1/5x) - 3

What is the equation of a line that is perpendicular to the line that goes through the points (0, -3) and (-3, 12)? y = 15x + 2 y = (-1/15x) - 8 y = -9x - 7 y = (1/5x) - 3
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What is the equation of a line that is perpendicular to the line that goes through the points (0, -3) and (-3, 12)?

y = 15x + 2
y = (-1/15x) - 8
y = -9x - 7
y = (1/5x) - 3

User Matt Van Horn
by
7.8k points

1 Answer

3 votes
Hello,

Slope of the line passing through the points:
m=(12+3)(-3-0)=-5
Slope of the perpendicular: 1/5

==> Answer D.
User Rpf
by
7.9k points
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