Question

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that

A) it is a reactant in one intermediate reaction and a catalyst in the other reaction.
B) it is a product in one intermediate reaction and a catalyst in the other reaction.
C) it is a reactant in one intermediate reaction and a product in the other reaction.
D) it is a reactant in both of the intermediate reactions.

Answer 1

The right answer for the question that is being asked and shown above is that: "C) it is a reactant in one intermediate reaction and a product in the other reaction." When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that it is a reactant in one intermediate reaction and a product in the other reaction.

Answer 2

Answer: Option (C) is the correct option.

Step-by-step explanation:

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that it is a reactant in one intermediate reaction and a product in the other reaction.

For example,

`2Al(s) + 2KOH(aq) + 6H_(2)O\rightarrow 2KAl(OH)_(4)(aq)+ 3H_(2)(g)` ....(1)

`2KAl(OH)_(4)(aq) + 4H_(2)SO_(4)(aq) + 6H_(2)O(l)\rightarrow 2KAl(SO_(4))_(2)(aq)+ 12H_(2)O(s)` .........(2)

Cancelling the common species in both the equations as follows.

`2Al(s) + 2KOH(aq) + 6H_(2)O\rightarrow \\ot{2KAl(OH)_(4)(aq)}+ 3H_(2)(g)`

`\\ot{2KAl(OH)_(4)(aq)}+ 4H_(2)SO_(4)(aq) + 6H_(2)O(l)\rightarrow 2KAl(SO_(4))_(2)(aq)+ 12H_(2)O(s)`

Therefore, on addition we get the equation as follows.

`2Al(s)+ 2KOH(aq) + 4H_(2)SO_(4)(aq) + 22H_(2)O(l)\rightarrow 3H_(2)(g)+ 2KAl(SO_(4))_(2) + 12H_(2)O(s)`