Question

How to factor 2n^2+3n-9 without splitting the middle term

Answer 1

`2n^2+3n-9= \\\\ a=2 \\ b=3 \\ c=-9 \\\\ \Delta= 3^2-4*2*(-9)=9+72\to\boxed{81} \\\\ x_1;x_2=(-3 +\-√(81))/(2*2)= (-3+/- 9)/(4) \\\\ x_1=(-3+9)/(4)=(6)/(4)\to\boxed{(3)/(2)} \\\\ x_2=(-3-9)/(4)=(-12)/(4)\to\boxed{-4} \\\\ 2n^2+3n-9=(x-(3)/(2))(\x+4)`