Question

Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant = b2 – 4ac

Answer 1

Hello,

Δ=0-4*(-2)*3=24

2 real solutions

Answer 2

There are two real, distinct roots to the quadratic equation .

Explanation:

Given : -2x² + 3 = 0.

To find : Determine the discriminant and how many real number solutions does the equation have.

Solution : We have given -2x² + 3 = 0.

On comparing ax²+bx +c = 0

Discriminant = b² - 4ac

Where b = -2 , c = 3

Plugging the values

D = ( -2)² - 4 ( -2) ( 3) .

D = 4 + 24 .

D = 28 > 0

If the discriminant is greater than zero, this means that the quadratic equation has two real, distinct (different) roots.

Therefore, There are two real, distinct roots to the quadratic equation .