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In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 125.0 milliliters of a 6.0 M HCl in an excess of Mg?

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The balanced reaction is:

Mg (s) + 2HCl (aq) = H2 (g) + MgCl2 (aq) We are given the amount of reactants to be reacted. This will be the starting point of the calculations. .125 L HCl solution (6.0 mol HCl / L solution) ( 1 mol H2 / 2 mol HCl ) ( 2.02 g H2 / 1 mol H2 ) = 0.76 g H2
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