Question

A solution has a (oh-) = 8.6 × 10-5 the poh=, ph=, (h+)=

Answer 1

The pOH of the solution is approximately 4.07, the pH is 9.93, and the hydrogen ion concentration [H+] is approximately 1.17 x 10^-10 M.

Step-by-step explanation:

You're asking how to calculate the pOH, pH, and the concentration of hydrogen ions ([H+]) given the concentration of hydroxide ions ([OH-] = 8.6 × 10-5). To start with, pOH is the negative logarithm of the hydroxide ion concentration:

pOH = -log [OH-]

So, let's calculate the pOH:

pOH = -log(8.6 × 10-5) ≈ 4.07

Next, we can find the pH using the relationship pH + pOH = 14:

pH = 14 - pOH ≈ 14 - 4.07 = 9.93

At 25 °C, pH and pOH always add up to 14. As for the hydrogen ion concentration, it is related to the pH:

[H+] = 10-pH = 10-9.93 ≈ 1.17 × 10-10

Therefore, the pOH of the solution is 4.07, the pH is 9.93, and the concentration of hydrogen ions [H+] is approximately 1.17 x 10-10 M.

Answer 2

pOh is calculated by the negative logarithm of hydroxide ions concentration. From the given value, we have:

pOH = -log(8.6 x 10 ^-5)
pOH = 4.07

To calculate the pH we use the relation of pOH and pH, expressed as:

14 = pOH + pH
pH = 14 - 4.07 = 9.93
pH = -log [H+]
[H+] = 10^-9.93 = 1.16 x 10^-3 M