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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Which equations can be used to solve for y, the length of the room? Check all that apply.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

2 Answers

0 votes
Hello,

A:False
B:True
C:True
D:False
E:True


User Morsik
by
8.4k points
5 votes

Answer:

Option B , C and E are correct


y^2-5y =750


750 -y(y-5)=0

(y+25)(y-30)=0

Explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle =
length * width

Substitute the given values in above formula we get;


750 = y(y-5) ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒
y(y-5) =750 or


y^2-5y =750 or


y^2-5y-750=0


y^2-25y+30y-750=0

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;


y^2-5y =750 ,
750 -y(y-5)=0 and (y+25)(y-30)=0




User Cyrus Mohammadian
by
8.4k points

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