Question

What was the temperature of 180 L of acetone before it was heated to 72 C and increased to a volume of 210 L (consider acetone as an ideal gas)

Answer 1

In order to determine the initial termperature of the acetone, consider it as an idel gas. Then, you can write the following relation between volumes and temperatures:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

In this case, consider that the pressure is constant, then, P1=P2=P.

You cancel out pressure from the previous equation, solve for T1 and replace the values of the other parameters, as follow:

`\begin{gathered} T_1=T_2(V_1)/(V_2) \\ T_1=(72C)((180L)/(210L)) \\ T_1\approx61.7C \end{gathered}`

Hence, the initial temperature of the acetone was approximately 61.7°C