Question

A 64.0g sample of methanol requires 1.61kJ of heat to raise its temperature from 22.0 ℃ to 32.0℃. Find thespecific heat capacity of methanol.

Answer 1

Step-by-step explanation:

The following formula is used to calculate the specific heat of substances:

c = Q/m. ΔT

Where,

c: specific heat (cal/g.°C or J/Kg.K)

Q: amount of heat (cal or J)

m: mass (g or kg)

ΔT: temperature variation (°C or K)

C: heat capacity (cal/°C or J/K)

In the International System (SI), specific heat is measured in J/Kg.K (Joule per kilogram and per Kelvin). However, it is very common to be measured in cal/g.°C (calorie per gram and per degree Celsius).

1 cal = 4.186 J

First, let's transform Joule into Cal:

1 cal ---- 4.186 J

x cal ---- 1,610 J

x = 384.6 cal

Second:

Find ΔT

ΔT = 32 - 22 = 10

Now let's replace these values in the formula:

c = 384.6/64*10

c = 0.6 cal/g.°C

Answer: c = 0.6 cal/g.°C