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How many moles of I2 will form 3.58 g of NI3?
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1 vote
How many moles of I2 will form 3.58 g of NI3?

User Kubra
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1 Answer

4 votes

1. The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed. This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.

User Thiago Pereira
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