Question

A 25,000 kg jet is sitting still on the runway (O

m/s). If the jet goes to take off and reaches 80
m/s in 10 seconds, how much force was required
to get it there?

Answer 1

The force required to get it there is 200000 N.

Step-by-step explanation:

The force can be calculated by the second Newton's law:

`F = ma`

Where:

m: is the mass = 25000 kg

a: is the acceleration

The acceleration is given by:

`a = (v)/(t)`

Where:

v: is the velocity = 80 m/s

t: is the time = 10 s

`a = (v)/(t) = (80 m/s)/(10 s) = 8 m/s^(2)`

Hence, the force is:

`F = ma = 25000 kg*8 m/s^(2) = 200000 N`

Therefore, the force required to get it there is 200000 N.

I hope it helps you!