Question

Line AB contains points A (1, 2) and B (−2, 6) The slope of line AB is

a)zero
b)undefined
c)positive
d)negative


The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?
Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is
Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are
The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).
The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are

parallel because the product of the slopes is −1

perpendicular because the product of the slopes is −1

parallel because the slopes are the same

perpendicular because the slopes are the same



Question 2

(06.02 LC)

The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

1 over 2

2

negative 1 over 2

−2



Question 3

(06.02 LC)

Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is

zero

undefined

positive

negative



Question 4

(06.02 MC)

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

y = 2x + 16

y = negative 1 over 2x + 17 over 2

y = − 1 over 2x + 7 over 2

y = 2x − 4



Question 5

(06.02 MC)

The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

y = −2x + 13

y = negative 1 over 2x + 7

y = 1 over 2x + 3

y = − 2x − 3

Answer 1

the answers to all of the questions are D,A,A,D,A

Explanation:

Answer 2

On the first question, the formula would be m=\frac{y2-y1}{x2-x1} and the value we got is -4/3, so D.
On the second quesiton, the slope in the given equation of the line is -2, its negative reciprocal is 1/2, so A.
On the third question, use the slope formula above and the value you would get is zero, so A.
On the fourth question, the equation of the line perpendicular to line QR is y=2x+b, to find b, just substitute the point (5,6) to the equation. That would make b = -4. the final equation of the line would be: y=2x-4, so D.
On the fifth question, the equation of the line parallel to line QR is y = -2x + b. substitute the point (4,5) to the equation, and you'll get b = 13. the final equation of the line would be y=-2x+13, so A.