Question

There are 200 students in the 7th grade class at Manchester Middle School. Of these students, 22% play football and 12% play baseball. Eight students play on both teams. What is the probability that a student plays either football or baseball?

Answer 1

Answer: There is 30% student plays either football or baseball.

Explanation:

Since we have given that

Total number of students = 200

Percentage of students who play football = 22%

Number of students who play football n(F) is given by

`0.22* 200\\\\=44`

Percentage of students who play baseball = 12%

Number of students who play baseball n(B) is given by

`0.12* 200\\\\=24`

Number of students who play on both teams n(F∩B) = 8

According to rules, it becomes,

`n(F\cap B)=n(F)+n(B)-n(F\cap B)\\\\n(F\cap B)=44+24-8=60`

Probability that a student plays either football or baseball is given by

`(60)/(200)\\\\=0.3\\\\=30\%`

Hence, there is 30% student plays either football or baseball.