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The variables A, B, and C represent polynomials where A = x2, B = 3x + 2, and C = x – 3. What is AB – C2 in simplest form?

User Privateace
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2 Answers

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AB - C2 = (x2)(3x + 2) - (x-3)2
AB - C2 = 3x3 + 2x2 - (x2 -6x +9)
AB - C2 = = 3x3 + 2x2 - x2 + 6x - 9
AB - C2 = = 3x3 + x2 + 6x - 9
User Vangorra
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6.8k points
4 votes

Answer:


AB-C^2 in simplest form:


3x^3+x^2+6x-9

Explanation:

The distributive property says that:


a \cdot (b+c) =a\cdot b+ a\cdot c

Given that:

The variables A, B, and C represent polynomials

Where,


A = x^2


B = 3x+2


C = x-3

We have to find the
AB-C^2

then;


AB-C^2 =
(x^2)(3x+2)-(x-3)^2

Apply the distributive property :


(3x^3+2x^2)-(x-3)^2


3x^3+2x^2-(x^2+9-6x)

Remove the bracket, we have;


3x^3+2x^2-x^2-9+6x

Combine like terms;


3x^3+x^2+6x-9

Therefore,
AB-C^2 in simplest form:
3x^3+x^2+6x-9

User Cheekoo
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