Question

A rigid container of O2 has a pressure of 340 kPa at a temperature of 713 K. what is the pressure at 273 K

Answer 1

P1/T1 = p2/T2

340/ 713 = p2/ 273
p2 = 340 x 273/ 713 = 130 kPa

Answer 2

Answer: The pressure at 273 K is 130 kPa.

Solution:- From Gay-Lussac's law, "At constant volume, the pressure of a given mass of a gas is directly proportional to the kelvin temperature."

The equation used for this is written as:

`(P_1)/(T_1)=(P_2)/(T_2)`

Where,
`P_1` is the pressure at
`T_1` temperature and
`P_2` is the pressure at
`T_2` temperature.

Temperatures are already given in kelvin so no need to do the conversion. Let's plug in the values and calculate the new pressure.

`(340kPa)/(713K)=(O_2)/(273K)`

On rearranging this for new pressure:

`P_2=(340kPa*273K)/(713K)`

`P_2=130kPa`