92.2k views
4 votes
The radioisotope radon-222 has half-life of 3.8 days. how much of a 73.9-g sample of radon-222 would be left after approximately 23 days?

User Perel
by
7.8k points

1 Answer

3 votes
This can be solved by the equation:

A = Aoe^(-ln2/t)T
where Ao is the initial amount of the substance ( 73.9-g sample of radon-222 ), t is the half-life time (3.8 days) and T is the time elapsed. Plugging in the values in the equation, the substance left is 1.11g.
User Dan Leveille
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.