Question

A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?

Answer 1

0.034 newtons/amp·meter

Answer 2

Magnetic field strength, B = 5.95 Tesla

Step-by-step explanation:

It is given that,

Length of wire, l = 0.36 m

It is moving perpendicularly through a magnetic field at a speed of, v = 0.21 m/s

Induced emf, E = 0.45 volts

The mathematical expression for induced emf is given by :

`E=(d\phi)/(dt)=Blv`

`(d\phi)/(dt)` is the rate of change of magnetic flux,

B is magnetic field

So,
`B=(E)/(lv)`

`B=(0.45)/(0.36* 0.21)`

B = 5.95 Tesla

Hence, this is the required solution.