Question

What would be the volume in liters of an ideal gas, if a 0.111 mole sample of the gas had a temperature of 1130 degrees Celsius at a pressure of 5.45 atmospheres? (The ideal gas constant is 0.0821 L•atm/mol•K.)

0.43 liters

1.43 liters

1.89 liters

2.35 liters

Answer 1

Answer: Option (d) is the correct answer.

Step-by-step explanation:

The given data is as follows.

n = 0.111 mole, T = 1130 degrees Celsius = 1130 + 273 = 1403 K

P = 5.45 atm, V = ?

R = 0.0821 L atm/mol K

Using the ideal gas equation, we can calculate the volume as follows.

PV = nRT

or, V =
`(nRT)/(P)`

=
`(0.111 mole * 0.0821 L atm/mol K * 1403 K)/(5.45 atm)`

=
`(12.786 L)/(5.45)`

= 2.346 L

or, = 2.35 L (approx)

Thus, we can conclude that volume of the ideal gas is 2.35 liters.

Answer 2

It is implied that the gas is ideal. The given parameters are: P=5.45, T=1130degC, n=0.111moles and ideal gas constant is 0.0821 L•atm/mol•K. The Ideal gas equation is PV=nRT. Note: All units are consistent. Plug in the values and you get an answer of 2.35L.