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A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. What's the maximum height it will reach?

a. 35.4 m
b. 63.5 m
c. 82.1 m
d. 127.0 m

User Cbel
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1 Answer

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This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked.

Informtion needed:
Acceleration due to gravity = 9.81m/s^2

Formula:

Hmax = ((V^2)(sin(angle))^2)/2g
Hmax = ((50^2)(sin45)^2)/(2*9.81) = 63.71 or letter B 63.5 m is the closest answer.
User Kulgar
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