Question

What is the product of d – 9 and 2d2 + 11d – 4?

A=2d3 – 7d2 – 103d + 36
B=2d3 – 7d2 – 95d + 36
C=2d3 + 7d2 – 95d + 36
D=2d3 + 7d2 – 103d + 36

Answer 1

(A)
`2d^3-7d^2-103d+36`

Explanation:

It is given that there are two functions that are
`(d-9)` and
`2d^2+11d-4` and

We have to find the product of
`(d-9)` and
`2d^2+11d-4`, therefore we can write as:

`(d-9)(2d^2+11d-4)`

`2d^3-18d^2+11d^2-99d-4d+36`

`2d^3-7d^2-103d+36`

which is the required product.

Thus, Option A is correct.

Answer 2

`2d^3-7d^2-103d+36`

A is the correct option.

Explanation:

We have to find the product

`(d-9)(2d^2+11d-4)`

Using the distributive property (term by term multiplication), we have

`d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)`

On multiplying, we get

`2d^3+11d^2-4d-18d^2-99d+36`

Combine like terms

`2d^3-7d^2-103d+36`

A is the correct option.