Question

B2-4b+4=0 using quadratic forumla

Answer 1

Before using the quadratic, make sure the right side is equal to 0. Check.

The quadratic formula gives the solution for an equation ,

which is .

In this case, our "a" value can be considered 1, b = -4, and c = 4.

Let's plug these values into the quadratic formula.

Another easy way to solve would be by factoring.

We would find two numbers that add to b and mutliply to equal ac.

Split our bx term into these two values

Factor and simplify.

(These numbers would be -2 and -2. Then we'd get

b² - 2b - 2b + 4. Factor the first two terms...

b(b-2) - 2b + 4. Factor the last two so that you get the same thing in the ()'s

b(b-2) -2(b-2) Combine like terms.

(b-2)(b-2) or (b-2)² is our factored form.

This is going to be equal to zero, so (b-2)² = 0.

We then look at our factors and note that any number which can cause it to equal zero is correct. Both factors are (b-2). In that case, b=2.

There's also a lot of shortcuts you could've done there such as taking the two numbers you got (say, m and n) and putting them directly into (x+n)(x+m) whenever your a value is 1.)

Explanation:

trust me !

Answer 2

Trying to factor by splitting the middle term

Factoring b2-4b+4
The first term is, b2 its coefficient is 1 .
The middle term is, -4b its coefficient is -4 .
The last term, "the constant", is +4

Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4

Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -4 .

-4 + -1 = -5 -2 + -2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
b2 - 2b - 2b - 4

Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-2)
Add up the last 2 terms, pulling out common factors :
2 • (b-2)
Step-5 : Add up the four terms of step 4 :
(b-2) • (b-2)
Which is the desired factorization