138k views
4 votes
Which of the following is the equation of a circle with a radius of 2.5 and its center at (4,- 3)?

(x - 4)^2 + (y + 3)^2= 2.5

(x - 4)^2 + (y + 3)^2= 6.25

(x - 4)^2 + (y- 3)^2= 2.5

(x - 4)^2 + (y - 3)^2= 6.25

User Summoner
by
9.0k points

2 Answers

5 votes
Hello,

Answer B

(x-4)²+(y+3)²=2.5²=6.25


User Bartjan
by
8.4k points
5 votes

Answer:

(x - 4)^2 + (y + 3)^2= 6.25

Explanation:

To solve this problem, we need to remember the formula to find the equation of a circle of radius r and center in (h,k):
(x-h)^(2) +(y-k)^(2) = r^(2)

Now we need to substitute the values given in the problem.

We have r = 2.5, h = 4, r = -3


(x-h)^(2) +(y-k)^(2) = r^(2)\\(x-4)^(2) +(y-(-3))^(2)=2.5^(2)  \\(x-4)^(2)+(y+3)^(2)  =6.25

Therefore, the correct option would be B)

User Willem Meints
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories