Mass of H₂ produced = 12 g
Further explanation
Given
32 grams of CH₄
Required
mass of H₂
Solution
Reaction
CH₄ + H₂O (+ heat) → CO + 3H₂
mol CH₄(MW= 16 g/mol) :
= mass : MW
= 32 g : 16 g/mol
= 2
From the equation, mol ratio CH₄ : H₂ = 1 : 3, so mol H₂ :
= 3/1 x mol CH₄
= 3/1 x 2
= 6
Mass H₂(MW = 2 g/mol) :
= mol x MW
= 6 x 2
= 12 g