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5 votes
Solve the equation. Write your answers in exact, simplified form.48q^3+32q^2-27q-18=0

User Teun Kooijman
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1 Answer

18 votes
18 votes

Given an equation to solve:


48q^3+32q^2-27q-18=0

let us solve,


\begin{gathered} 48q^3+32q^2-27q-18=0 \\ \mleft(3q+2\mright)\mleft(4q+3\mright)\mleft(4q-3\mright)=0 \\ 3q+2=0 \\ 4q+3=0 \\ 4q-3=0 \end{gathered}
\begin{gathered} 3q+2=0 \\ q=-(3)/(2) \end{gathered}
\begin{gathered} \: 4q+3=0 \\ q=-(3)/(4) \end{gathered}
\begin{gathered} 4q-3=0 \\ q=(3)/(4) \end{gathered}

The solutions are,


q=-(2)/(3),\: q=-(3)/(4),\: q=(3)/(4)

User Tez Wingfield
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2.6k points