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Find the equation of the circle whose center and radius are given.

center ( -2, -5), radius = 1

User Beeker
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2 Answers

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as i said before put the center instead of (h,k) in the general formula and put r=1
so (x-(-2))^2 + (y-(-5)^2 = 1
(x+2)^2 + (y+5)^2 = 1
User Bentesha
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4 votes

Answer: The required equation of the circle is
x^2+y^2+4x+10y+28=0.

Step-by-step explanation: We are given to find the equation of the circle with center (-2, -5) and radius of length 1 unit.

We know that

the standard equation of a circle with center (h, k) and radius of length r units is given by


(x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

For the given circle, we have

center, (h, k) = (-2, -5) and radius, r = 1 units.

Therefore, from equation (i), we get


(x-(-2))^2+(y-(-5))^2=1^2\\\\\Rightarrow (x+2)^2+(y+5)^2=1\\\\\Rightarrow x^2+4x+4+y^2+10x+25=1\\\\\Rightarrow x^2+y^2+4x+10y+29-1=0\\\\\Rightarrow x^2+y^2+4x+10y+28=0.

Thus, the required equation of the circle is
x^2+y^2+4x+10y+28=0.

User Ojas Mohril
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