Step-by-step explanation:
Before we find the number of particles we have to convert from grams to moles. To do that we can use the molar mass of our compound.
molar mass of Cr = 52.00 g/mol
molar mass of S = 32.07 g/mol
molar mass of O = 16.00 g/mol
molar mass of CrSO₃ = 1 * 52.00 g/mol + 1 * 32.07 g/mol + 3 * 16.00 g/mol
molar mass of to c = 132.07 g/mol
mass of onver = 750 g
moles of tles = 750 g/(132.07 g/mol)
moles of we ha = 5.68 molesvles we haCrSO₃CrSO₃CrSO₃CrSO₃
According to Avogadro's Number we have 6.022 * 10^23 particles in 1 mol of molCr. Let's use that relationship to find the answer to our problem.
1 mol of SO₃Cr = SO₃6.022 * 10^23 partic
n° of particles = 5.68 moles * 6.022 * 10^23 particles/(1 mol)
n° of particles = 3.42 * 10^24 particles
Answer: there are 3.42 * 10^24 particles.