Question

What percentage of a radioactive species would be found as daughter material after five half-lives?

Answer 1

i believe the answer is e on plato

Explanation:

Answer 2

The answer is 3.125%.

The relation between number of half-lives (n) and amount of sample that remained (x) can be expressed as:

`(1/2)^(n) =x`

It is given:
n = 5

To find x, we will change n in the equation with five:


`(1/2)^(n) =x`
⇒
`(1/2)^(5) =x`
⇒
`0.5^(5) =x`
⇒
`x=0.03125 = (3.125)/(100) = 3.125%`

Therefore, 3.125% of a radioactive species would be found as daughter material after five half-lives.