Question

Find the parametrization for the circle with center at (-3,2) and with radius = 3

Answer 1

`(x+3)^(2) + (y-2)^(2) =9`

Working;
From the general equation of a circle;

`(x-h)^(2) + (y-k)^(2) = r^(2)`
This gives;

`(x--3)^(2)+ (y-2)^(2) = 3^(2)`
This gives;

`(x+3)^(2) + (y-2)^(2) =9`