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A survey 1500 commuters in New York City showed that 1150 take the subway 680 take the bus and 170 do not take either A) how many take the bus and subway B) how many only take the subway

User Nicolas Guillaume
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2 Answers

7 votes
7 votes

Final answer:

In the survey, 500 people take both the bus and the subway, and 650 people only take the subway. Calculations are based on the provided figures and accounting for people who take both modes of transport or neither.

Step-by-step explanation:

We can use a Venn diagram to solve this problem, but for this explanation, we will use equations. There are a total of 1500 commuters. We are given that 1150 take the subway, 680 take the bus, and 170 do not take either the bus or the subway.

Part A: How many take both the bus and the subway?

To find the number of people who take both the bus and the subway, we can add the number of subway riders and bus riders, then subtract the total number of commuters and those who don't take either mode of transportation to avoid double counting. So, the calculation is 1150 (subway) + 680 (bus) - 1500 (total commuters) + 170 (neither). Let's denote by B the number of people who take both the bus and the subway:
1150 + 680 - B = 1500 - 170
B = 1150 + 680 - 1500 + 170
B = 500

Therefore, 500 people take both the bus and the subway.

Part B: How many only take the subway?

To find the number of people who only take the subway, we subtract the number of people who take both the bus and the subway from the total number of subway riders:
1150 (total subway riders) - 500 (both bus and subway) = 650

Therefore, 650 people only take the subway.

User Batilc
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14 votes
14 votes

Step-by-step explanation:

Given;

We are given the following information;


\begin{gathered} All\text{ }commuters=1500 \\ Subway=1150 \\ Bus=680 \\ Neither=170 \end{gathered}

Required;

We are required to find how many commuters take the bus and subway. Also how many take the subwa only.

Step-by-step solution;

Since we have a survey of 1500 commuters, the universal set will be 1500, that is


U=1500

Then the set that contains tiose who take the subway is;


w=1150

The set that contains those who take the bus is;


b=680

Also we are told that 170 take neither the subway nor the bus, the this set is;


n=170

Now we know that 170 who take neither the subway nor the bus belongs to the universal set but not to either of w or b.

This means;


\begin{gathered} (n)=(U)-(w\cup b) \\ 170=(U)-(w\cup b) \\ 170=1500-(w\cup b) \end{gathered}

We can collect like terms;


\begin{gathered} (w\cup b)=1500-170 \\ (w\cup b)=1330 \end{gathered}

This means there is a total of 1330 commuters who travel by both subway and by bus.

To calculate commuters who take both the subway and the bus;


\begin{gathered} (w\cup b)=(w)+(b)-(w\cap b) \\ 1330=1150+680-(w\cap b) \\ 1330=1830-(w\cap b) \end{gathered}
\begin{gathered} (w\cap b)=1830-1330 \\ (w\cap b)=500 \end{gathered}

This means there are 500 commuters who travel by both the subway and the bus.

Commuters who take only the subway is derived by removing those who take both subway and bus from those who take the subway. That is;


Number\text{ }who\text{ }take\text{ }only\text{ }subway=(w_1)
\begin{gathered} (w_1)=(w)-(w\cap b) \\ (w_1)=1150-500 \\ (w_1)=650 \end{gathered}

Therefore,

ANSWER:


\begin{gathered} (a)\text{ }500\text{ }take\text{ }the\text{ }bus\text{ }and\text{ }subway \\ (b)650\text{ }take\text{ }only\text{ }the\text{ }subway \end{gathered}

User Johnny Wey
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2.8k points
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