Question

Which of these expressions yields the speed of sound in air in SI units if the air temperature is 163 degrees Celsius? [Describe the properties of sound waves] 331.5 divided by 0.607 times 163 331.5 + 0.607 times 163 331.5 times 0.607 times 163

Answer 1

Given:

the temperature of the air is

`T=163\text{ C}`

Required: velocity of the wave in air

Explanation: At normal atmospheric pressure, the temperature dependence of the speed of wave is given by

`v=331\text{ m/s +0.6 m/s}* T`

Plugging the value of T in above relation we get

`v=331\text{ m/s+ 0.6 m/s}*163\text{ }`

Thus, the speed of the wave is

`331\text{ m/s+ 0.607 times 163}`