Question

For what value of k will these pairs of simultaneous equations have no solution?

kx – 3y = k and y = 4x + 1

Answer 1

kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
`(k+3)/(k-12)`
Also y=
`(5k)/(k-12)`
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.