Question

What is the pressure of 5.0 mol nitrogen gas in a 2.0 L container at 286 K

Answer 1

The "Ideal Gas Law Equations" is

`PV=nRT`
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or number (in moles)
R= 8.3145
`(Pascals*Liters)/(Moles*Kelvin)` or
`(PaL)/(molK)`
T= Temperature (In Kelvin)


`P= (nRT)/(V)`

Plug into the equation and you're good!

`P=(nRT)/(V)`

`P =((5mol)(8.3145)(286K))/(2L)`

`P=5944.8675Pa`

If your teacher cares about sig figs,
2 sig figs (significant figures)

`P=5900Pa`

For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar