Question

ANYONE???????? 

PLZ HELP ASAP:Indicate in standard form the equation of the line through the given points.
K(6, 4), L(-6, 4)

Can you lead me through the steps because I'm not getting this at all...

Answer 1

Equation of a straight line: y = mx + c. m is the gradient while c is the y-intercept.
gradient m = (y2 - y1) / ( x2 - x1)
from the given coordinates, x1 = 6, x2 = -6, y1= 4, y2 = 4
m = (4 - 4) / ( -6 - 6) = 0/12 = 0
to find y- intercept, we solve for c using any of the given coordinates.
4 = 0x + c
c = 4
the equation of the line: y = 0x + 4
Standard form = ax + by = c
0x + y = 4
y = 4