Register

I don't know what method I should use to solve for y in this equation: (y-3)^2=4y-12

I don't know what method I should use to solve for y in this equation: (y-3)^2=4y-12
17.1k views
1 vote
I don't know what method I should use to solve for y in this equation: (y-3)^2=4y-12

User Erick Mwazonga
by
8.1k points

1 Answer

3 votes
(y-3)^2 -4y +12 = 0
[y^2 -6y +9] -4y +12 =0
y^2 -10y + 21 = 0
(y -3) (y-7) =0
y=3 ; y = 7
User Mojtaba Barari
by
7.9k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!