Question

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Answer 1

work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20

Answer 2

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Step-by-step explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

`W = F * d`

Where, W = work

F = force

d = distance

Put the value into the formula of work

`W= 1500*40`

`W = 60000\ Pounds-feet`

Power:

The power is equal to the work done divided by time.

The power is defined as,

`P = (W)/(t)`

Where, P = power

W = work

t = time

Put the value into the formula of power

`P = (60000)/(20)`

`P=3000\ Pounds-feet/s`

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.