Question

A conducting sphere 2.0 cm in diameter with a charge of 4 nC. The surface electric field strength is ?× N/C

Answer 1

The diameter of the conducting sphere is d = 2 cm.

The radius of the conducting sphere will be

`\begin{gathered} r=(d)/(2)=\frac{2*10^(-2)\text{ m}}{2} \\ =1\text{ }*10^(-2)\text{ m} \end{gathered}`

The charge on the sphere is

`\begin{gathered} q=\text{ 4 nC } \\ =\text{ 4}*10^(-9)\text{ C} \end{gathered}`

The force on the surface due to the charge is

`\begin{gathered} F=(1)/(4\pi\epsilon_0)*(q)/(r^2) \\ =(9*10^9*4*10^(-9))/(1*10^(-4)) \\ =36*10^4\text{ C} \end{gathered}`

So, the surface electric field strength will be