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1 vote
Which of the following is the greatest common factor of the terms 48s5t3u2 and 40s3tu4?

a. 6s2t2u
b. 6s3tu
c. 8s2t2u
d. 8s3tu2

User Zhihar
by
7.9k points

2 Answers

3 votes
48s^5t^3u^2 = 8s^3tu^2 * 6s^2t^2

40s^3tu^4 = 8s^3tu^2 * 5u^2

Answer: D: 8 s^3 t u^2





User EmilMachine
by
8.0k points
7 votes

Answer: Option 'd' is correct.

Explanation:

Since we have given that


48s^5t^3u^2\ and\ 40s^3tu^4

We need to find the greatest common factor of the above terms:


48s^5t^3u^2=2* 2* 2* 2* 3* s^5* t^3* u^2\\\\And,\\\\40s^3tu^4=2* 2* 2* s^5* t* u^4\\\\Greatest\ common\ factor=2^3* s^3* t* u^2=8s^3tu^2

Hence, Option 'd' is correct.

User Karl Johansson
by
7.7k points