Question

The thunderbolt bobsled team is training for Olympic Gold. During practice they start a run with a speed of 0.57 m/s, they complete the 1360 m run in 89.49 seconds. What is the acceleration of the sled?

Answer 1

`acceleration=(\Delta\ velocity)/(\Delta\ time)\\\\ v_(initial)=0,57m/s\\ distance=1360m\\ \Delta\ time=89,49seconds\\\\ v_(final)-v_(initial)=(distance)/(time)\\ v_(final)=(distance)/(time)+v_(initial)\\ v_(final)=(1360)/(89,49)+0,57\\\\v_(final)=15,77(m)/(s)\\\\ acceleration=(15,77-0,57)/(89,49)=0,17(m)/(s^2)\\\\ \boxed{acceleration=0,17(m)/(s^2)}`