48,165 views
36 votes
36 votes
Can someone please help me find the answer to.the following

Can someone please help me find the answer to.the following-example-1
User Dimitra
by
3.2k points

1 Answer

11 votes
11 votes

As given in the question, ABCD is a square. The angles between the sides of the square are always 90°. The diagonal divides this angle exactly into two halves.

Therefore, the angle BCA is


\angle BCA=(90^0)/(2)=45^0^{}_{}

The total angle at the centre where the diagonals meet is 360°.

These diagonals cut it into four equal parts.

Therefore, angle AWD is


\angle AWD=(360^0)/(4)=90^0

User Eric Mentele
by
3.3k points