Question

A sample of gas at 300 K has a volume of 2.0 liters. At what temperature will the volume decrease to 1.0 liter if the pressure is kept constant?

Answer 1

pv/t=c
Therefore

v/t=c
2/300=1/t2
t2=150K

Answer 2

Answer : The temperature will be, 150 K

Explanation :

Charles' Law : This law states that volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T` (At constant pressure and number of moles)

or,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1` = initial volume of gas = 2.0 L

`V_2` = final volume of gas = 1.0 L

`T_1` = initial temperature of gas = 300 K

`T_2` = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of gas.

`(2.0L)/(300K)=(1.0L)/(T_2)`

`T_2=150K`

Therefore, the temperature will be, 150 K