Question

Consider the function:h(x) = – 3x3 + 4x2 + 4x + 4Step 2 of 2: Find the value of h(6).

Answer 1

Given the function h(x)

`h(x)=-3x^3+4x^2+4x+4`

We will find the value of h(6)

So, substitute with (x =6) into the function h(x)

`\begin{gathered} h(6)=-3\cdot6^3+4\cdot6^2+4\cdot6+4 \\ h(6)=-3\cdot216+4\cdot36+24+4 \\ h(6)=-648+144+24+4 \\ \\ h(6)=-476 \end{gathered}`

So, the answer will be: h(6) = -476