Question

Lindsey needs a jeweler to repair her earrings. Jeweler A is offering her services for an initial $120 inaddition to $18 per hour. Jeweler B is offering his services for an initial $138 in addition to $15 per hour.When will the two jewelers charge the same amount of money?The two jewelers will charge the same amount of money afterhours.

Answer 1

Let C represent The total charge, and let H represent the number of hours

For Jeweler A, we have the equation:

C = 120 + 18H

For Jeweler B, we have the equation:

C = 138 + 15H

To find the time they will charge the same amount of money, equate both equations and solve for H.

Thus, we have:

120 + 18H = 138 + 15H

Subtract 15H from both sides:

120 + 18H - 15H = 138 + 15H - 15H

120 + 3H = 138

Subtract 120 from both sides:

120 - 120 + 3H = 138 - 120

3H = 18

Divide both sides by 3:

`\begin{gathered} (3H)/(3)=(18)/(3) \\ \\ H\text{ = 6} \end{gathered}`

Therefore, the two jewelers will charge the same amount of money after the 6 hours

ANSWER:

6 hours