186k views
11 votes
How many moles of LiF are present in 34.58 g?

O 0.3998 mol
O 1.333 mol
2.500 mol
36.32 mol

1 Answer

9 votes

Answer:

1.33moles

Step-by-step explanation:

Given parameters:

Mass of LiF = 34.58g

Unknown:

Number of moles of LiF = ?

Solution:

To solve this problem, we need to find the molar mass of LiF first.

Molar mass of LiF = 7 + 19 = 26g/mol

Number of moles of LiF =
(mass)/(molar mass)

So;

Number of moles of LiF =
(34.58)/(26) = 1.33moles

User Sas Gabriel
by
4.7k points