Answer:
Given: AC, DF, and GI are parallel.
Solution:
In ΔJAB and ΔJDE
∠J is common.
∠JAB=∠JDE→→As, AB║DE, so corresponding angles are equal.
ΔJAB ~ ΔJDE→→[AA similarity]
Similarly, we can prove that, ΔJ C B and ΔJ FE by AA similarity.
As, we know when triangles are similar their sides are proportional.

Option 4: BC is correct choice.