Question

What is the volume in liters occupied by 1.21 g ofFreon-12 gas, CC1,F₂, at 0.980 atm and 35°C?

Answer 1

`0.365\text{ L or 365 mL}`

Step-by-step explanation:

Here, we want to get the volume in liters occupied by the gas

From the ideal gas law:

`PV\text{ = nRT}`

This means:

`V\text{ = }(nRT)/(P)`

where:

n is the number of moles. To get this, we have to divide the mass given by the molar mass of the gas

The number of moles is as follows:

`\begin{gathered} mass\text{ = 1.21 g} \\ molar\text{ mass = 85.5 g/mol} \\ The\text{ number of moles:} \\ n\text{ = }(1.21)/(85.5)\text{ = 0.014152 mol} \end{gathered}`

R is the molar gas constant which is 0.0821 L.atm/mol.k

T is the temperature in Kelvin. We calculate this by adding 273.15 K to the temperature in Celsius (273.15 + 35 = 308.15 K)

P is the pressure of the gas which is 0.980 atm

V is the volume that we want to calculate

Substituting the values, we have it that:

`\begin{gathered} V\text{ = }(0.014152*0.0821*308.15)/(0.980)\text{ = 0.365 L} \\ or\text{ 365 mL} \end{gathered}`