Hello,
-3|6-x|<-15
==>|6-x|>5
1) if 6-x<0 then |6-x|=-6+x
==>-6+x>5==>x>11
2) if 6-x>0 then |6-x|=6-x
==>6-x>5==>6-5>x==>x<1
Solution is x<1 or x>11
---- -1 ------- 0 1 ----------- 11 ------------------------------
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