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Two forces of 30 pounds and 40 pounds act upon a body, forming an acute angle with each other. The angle between the resultant and the 30-pound force is 35degree 10'. Find, to the nearest ten minutes, the angle between the two given forces

User MorgoZ
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1 Answer

5 votes
angles in the triangle are
35°10'
180° - A (with A = angle between the 2 forces)
A - 35°10'

40/sin35°10' = 30/sin(A-35°10')
sin(A-35.17) = 30sin35.17°/40 = 0.432

A-35.17= 25.6
A = 60.77° = 60°46'
60°50'
User Andrzej Smyk
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