Question

A rigid cylinder contains a sample of gas at STP. What is the pressure of this gas after the sample is heated to 410 K?

(1) 1.0 atm (3) 0.67 atm
(2) 0.50 atm (4) 1.5 atm

Answer 1

Answer:(4) 1.5 atm

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas at STP= 1 atm

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas at STP = V L

`V_2` = final volume of gas = V L

`T_1` = initial temperature of gas at STP= 273K

`T_2` = final temperature of gas = 410 K

Now put all the given values in the above equation, we get the final pressure of gas.

`(1atm* VL)/(273K)=(P_2* VL)/(410K)`

`P_2=1.50atm`

Therefore, the pressure of gas will be 1.50 atm.