Given:
40.0g of water
25.0oC is raised to 60.0oC
Required:
Change in heat energy
Solution:
This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heat of the water is 4.18 J/g-K
Plugging in the values into the equation
H = mCpT
H = (40g) (4.18 J/g-K) (60 – 25)
H = 5,852 J